Archive for the ‘2014 Maths’ Category
FREE Download: 2014 Further Mathematics Trial Examination 1 Solutions
Friday, September 26th, 2014FREE Download: 2014 Further Mathematics Trial Examination 2
Friday, September 12th, 2014FREE Download: 2014 Further Mathematics Trial Examination 1
Sunday, September 7th, 2014FREE Download: 2014 Specialist Mathematics Trial Examination 2 Solutions
Sunday, August 31st, 2014FREE Download: 2014 Specialist Mathematics Trial Examination 1 Solutions
Sunday, August 31st, 2014FREE Download: 2014 Specialist Mathematics Trial Exam 1 Solutions – PDF 115KB
Thanks to Sam Hu for pointing out:
I was reading your 2014 free trial exam paper 1 for Specialist Maths and noticed an error to the solution of question 1. In part a, the question asks to simplify f(x) which results in a potential removal of a restriction to the original domain. Then in part b and c, it is important that the original domain which is R+ should be used instead of R\{0}. So the solution to part b should be [2, inf) and the graph in part c should have the right branch only.
FREE Download: 2014 Mathematical Methods CAS Trial Examination 2 Solutions
Thursday, August 21st, 2014FREE Download: 2014 Mathematical Methods CAS Trial Exam 2 Solutions – PDF 104KB
Thanks to Manishmao for pointing out that the solution to Q4e should be Pr(x<788|x>583.6), meaning the final answer would be 99.0%
FREE Download: 2014 Mathematical Methods CAS Examination 1 Solutions
Wednesday, August 13th, 2014FREE Download: 2014 Specialist Mathematics Trial Examination 2
Saturday, July 26th, 2014FREE Download: 2014 Specialist Mathematics Trial Examination 1
Saturday, July 26th, 2014FREE Download: 2014 Specialist Mathematics Trial Exam 1 – PDF 126KB
Thanks to Sam Hu for pointing out:
In the solution to question 3b, W(z) is supposed to be k(z+i) where k is a non-zero real number and was unfortunately missed out. To make k=1 so that the question is accessible, it would be necessary to add some information in the question such as ‘the leading coefficient of T(z) is 1’.